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Sunday, 19 January 2014

JAX-RS Send List using QueryParam Annotation

In this tutorial we are going to see how to send list to RESTful web service via URL using @QueryParam
1. Create new Dynamic web project by choosing File –> New –> Dynamic Web Project as given below.
2. Create the Project called RESTful-WebService
3. Add the following jar into WEF-INF/lib folder
add jar
4. Create package called com.javatutorialscorner.jaxrs.queryparam under RESTful-WebService
5. Create Java class QueryParamService under com.javatutorialscorner.jaxrs.queryparam package
QueryParamService .java
package com.javatutorialscorner.jaxrs.queryparam;

import java.util.List;

import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.QueryParam;
import javax.ws.rs.core.Response;

public class QueryParamService {

public Response getTutorial(@QueryParam("site") String site,
@QueryParam("tutorial") List<String> tutorial,
@QueryParam("rank") int rank) {
return Response
.entity("Web Site : " + site + " Tutorial : " + tutorial.toString()
+ " Rank : " + rank).build();

In above class @QueryParam used to get the value of URL query parameter into Java Class.

6.Configure Jersey Servlet Dispatcher

you need to configure REST as servlet in web.xml.


<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">



The servlet class available in jersey com.sun.jersey.spi.container.servlet.ServletContainer. The init param com.sun.jersey.config.property.package is used to define in which package jersey will look for the service classes.This package points to your resource class package. URL pattern is the part of base URL

Now you can run the service and access the service by calling the following URL


you can call the service by using web browser or from client class.

Web browser call


Create Client

Create package called com.javatutorialscorner.jaxrs.client under RESTful-WebService project

Create Client Java Class RESTfulClient under  com.javatutorialscorner.jaxrs.client package

RESTfulClient .java

package com.javatutorialscorner.jaxrs.client;

import com.sun.jersey.api.client.Client;
import com.sun.jersey.api.client.ClientResponse;
import com.sun.jersey.api.client.WebResource;
import com.sun.jersey.api.client.config.ClientConfig;
import com.sun.jersey.api.client.config.DefaultClientConfig;

public class RESTfulClient {

* @param args
public static void main(String[] args) {
// TODO Auto-generated method stub
String baseURI = "http://localhost:8080/RESTful-WebService";
ClientConfig config = new DefaultClientConfig();
Client client = Client.create(config);
WebResource service = client.resource(baseURI);
System.out.println("output for query param");
.queryParam("site", "www.javatutorialscorner.com")
.queryParam("tutorial", "RESTful WebService")
.queryParam("tutorial", "Java")
.queryParam("rank", "1").get(ClientResponse.class)


Now you can run the client and see the following output in console

output for query param

Web Site : www.javatutorialscorner.com  Tutorial : [RESTful WebService, Java] Rank : 1
Annamalai Thangaraj

Annamalai is a Sr.Software Engineer with 3+ years experience in Java, Spring, Struts, Hibernate, IDM/IAM, and Enterprise Web Application Development.

Website: Java Tutorials Corner

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Item Reviewed: JAX-RS Send List using QueryParam Annotation Rating: 5 Reviewed By: Annamalai Thangaraj